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https://github.com/Manoj-HV30/dsa-competitive-programming.git
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leetcode new problems
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class Solution {
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public:
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string longestCommonPrefix(vector<string>& strs) {
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if (strs.empty()) return "";
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string comm = "";
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int n = strs.size();
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for (int left = 0; left < strs[0].size(); left++) {
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char ch = strs[0][left];
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for (int i = 1; i < n; i++) {
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if (left >= strs[i].size() || strs[i][left] != ch) {
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return comm;
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}
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}
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comm += ch;
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}
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return comm;
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}
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};
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@@ -0,0 +1,5 @@
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Time complexity : O(n*m) where is n is the number of strings in the list and m is length of the shortest string
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space complexity : O(1)
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We start from first character of first string and compare it with all other strings, if no mismatch then add it to prefix string else return the prefix string
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